How to Handle File Uploads in Gin

Use c.Request.MultipartForm to parse the request body and access uploaded files via file, header, err := c.FormFile("name").

file, err := c.FormFile("file")
if err != nil {
    c.JSON(http.StatusBadRequest, gin.H{"error": err.Error()})
    return
}
src, err := file.Open()
if err != nil {
    c.JSON(http.StatusBadRequest, gin.H{"error": err.Error()})
    return
}
// Process src (io.Reader) here
src.Close()

Note: Ensure your form uses enctype="multipart/form-data" and set c.Request.MultipartForm if needed by calling c.Request.ParseMultipartForm(maxMemory) before accessing files.

Handling file uploads in Gin involves accepting a file from a web form in a Go web server using the Gin framework. You tell the server to expect a file, extract it from the request, and then read its contents like any other file. Think of it like receiving a package in the mail: you open the envelope (the request), take out the box (the file), and then look inside.