Fix: "cannot use type parameter in type assertion" in Go

Fix the 'cannot use type parameter in type assertion' error by asserting to 'any' first, then to the type parameter, or by using a direct type conversion.

You cannot use a type parameter directly in a type assertion because the compiler cannot verify the type at compile time. Instead, assert to any first, then perform a second assertion to the specific type parameter.

func Process[T any](v any) {
  // Step 1: Assert to any (or the interface T implements)
  if raw, ok := v.(any); ok {
    // Step 2: Assert to the specific type parameter
    if t, ok := raw.(T); ok {
      // Use t
    }
  }
}

If you know the value is already of type T, simply use a type conversion instead of an assertion:

func Process[T any](v any) {
  t := v.(T) // Panics if v is not T
  // Use t
}

Go needs to know exactly what type a variable is before it can check if it matches another type. Since a type parameter (like T) is a placeholder that could be anything, the compiler refuses to let you check against it directly. You must first check if the value is a generic type, then check if it matches your specific placeholder.